The correct answer is option 'B' - Short circuit.

Inductor behavior in steady state:
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In steady state conditions, the inductor acts as a short circuit. This means that the inductor offers very low impedance to the flow of current, allowing it to pass through easily.

Explanation:
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To understand why the inductor acts as a short circuit at steady state, we need to consider its behavior in an AC (alternating current) circuit.

An inductor is a passive electrical component that stores energy in its magnetic field when current flows through it. It consists of a coil of wire wound around a core. When an AC voltage is applied across an inductor, the current through it builds up gradually due to the opposing magnetic field generated by the coil.

Initially, when the AC voltage is applied, the inductor resists the change in current due to its property of self-inductance. As a result, it behaves as an open circuit, preventing the flow of current. However, as time progresses, the current through the inductor increases, and the magnetic field strengthens.

Once the current reaches a steady state, the inductor behaves differently. At this point, the inductor has reached its maximum current flow and the magnetic field is fully established. In this state, the inductor offers very low impedance to the AC current. The opposition to the flow of current that was present during the transient phase diminishes, and the inductor effectively becomes a short circuit, allowing the current to flow through it without significant resistance.

This behavior can be explained by the fact that in steady state, the inductor's reactance, which is the opposition it offers to the AC current due to its inductance, becomes negligible compared to its resistance. Since the reactance is very low, the inductor essentially acts as a short circuit, allowing the current to flow freely.

In summary, in steady state conditions, an inductor acts as a short circuit, offering very low impedance to the flow of current in an AC circuit.

A