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The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
  • a)
    4.37%
  • b)
    5%
  • c)
    6%
  • d)
    8.75%
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The population of a town increased from 1,75,000 to 2,62,500 in a deca...
Increase in 10 years = (262500 – 175000) = 875 00
Increase% = [(87500/175000) × 100] % = 50%
∴ Required average = (50/10) % = 5%
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Most Upvoted Answer
The population of a town increased from 1,75,000 to 2,62,500 in a deca...
To find the average percent increase of population per year, we need to calculate the annual growth rate.

Given:
Initial population = 1,75,000
Final population = 2,62,500

Step 1: Calculate the total increase in population
Total increase = Final population - Initial population
Total increase = 2,62,500 - 1,75,000
Total increase = 87,500

Step 2: Calculate the annual growth rate
Annual growth rate = (Total increase / Initial population) * 100
Annual growth rate = (87,500 / 1,75,000) * 100

Simplifying the above expression:
Annual growth rate = (0.5) * 100
Annual growth rate = 50

Step 3: Calculate the average percent increase per year
Average percent increase per year = Annual growth rate / Number of years
Number of years = 10 (given)

Average percent increase per year = 50 / 10
Average percent increase per year = 5%

Therefore, the average percent increase of population per year is 5%.

Hence, the correct answer is option 'B'
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The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:a)4.37%b)5%c)6%d)8.75%Correct answer is option 'B'. Can you explain this answer?
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