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The ‘‘trial'’ wavefuction for He atom is taken aswhere N is the normalization factor and Z ' is the variational parameter. Expression for the energy in terms of Z ' is found to beThen the lowest value of the energy ( E ') for He atom i s _________________(in a.u .)(Round off to two decimal places)Correct answer is between '-2.86,-2.82'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared
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The ‘‘trial'’ wavefuction for He atom is taken aswhere N is the normalization factor and Z ' is the variational parameter. Expression for the energy in terms of Z ' is found to beThen the lowest value of the energy ( E ') for He atom i s _________________(in a.u .)(Round off to two decimal places)Correct answer is between '-2.86,-2.82'. Can you explain this answer?, a detailed solution for The ‘‘trial'’ wavefuction for He atom is taken aswhere N is the normalization factor and Z ' is the variational parameter. Expression for the energy in terms of Z ' is found to beThen the lowest value of the energy ( E ') for He atom i s _________________(in a.u .)(Round off to two decimal places)Correct answer is between '-2.86,-2.82'. Can you explain this answer? has been provided alongside types of The ‘‘trial'’ wavefuction for He atom is taken aswhere N is the normalization factor and Z ' is the variational parameter. Expression for the energy in terms of Z ' is found to beThen the lowest value of the energy ( E ') for He atom i s _________________(in a.u .)(Round off to two decimal places)Correct answer is between '-2.86,-2.82'. Can you explain this answer? theory, EduRev gives you an
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