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The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer?.

Solutions for The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The enthalpy changes for the following processes are listed below : [2006]Cl2(g) → 2Cl(g), 242.3 kJ mol–1I2(g) → 2I(g), 151.0 kJ mol–1 ICl(g) → I(g) + Cl(g), 211.3 kJ mol–1I2(s) → I2(g), 62.76 kJ mol–1Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is : [2006]a)+16.8 kJ mol–1b)+244.8 kJ mol–1c)–14.6 kJ mol–1d)–16.8 kJ mol–1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.