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An aqueous solution containing 0.01 M FeCl3 and 0.06 M HClO4 has the same ionic strength as a solution of:
- a)0.09 M NaCl
- b)0.04 M Na2SO4
- c)0.06 M CuSO4
- d)0.03 M H3PO4
Correct answer is option 'B'. Can you explain this answer?
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An aqueous solution containing 0.01 M FeCl3 and 0.06 M HClO4 has the s...
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An aqueous solution containing 0.01 M FeCl3 and 0.06 M HClO4 has the s...
Explanation:
To determine which solution has the same ionic strength as the given solution, we need to calculate the total ionic strength of each solution and compare.
Definition:
Ionic strength is a measure of the concentration of ions in a solution. It is calculated by summing the products of the concentration of each ion and the square of its charge.
Calculating the ionic strength:
1. Given solution: 0.01 M FeCl3 + 0.06 M HClO4
- FeCl3 dissociates into Fe3+ and 3 Cl- ions.
- HClO4 dissociates into H+ and ClO4- ions.
- The ionic strength is calculated by multiplying the concentration of each ion by the square of its charge.
- For Fe3+, the concentration is 0.01 M and the charge is 3, so the contribution to the ionic strength is (0.01)(3^2) = 0.09.
- For Cl-, the concentration is 0.01 M (from FeCl3) + 0.06 M (from HClO4) = 0.07 M, and the charge is 1, so the contribution to the ionic strength is (0.07)(1^2) = 0.07.
- For H+, the concentration is 0.06 M (from HClO4) and the charge is 1, so the contribution to the ionic strength is (0.06)(1^2) = 0.06.
- For ClO4-, the concentration is 0.06 M (from HClO4) and the charge is 1, so the contribution to the ionic strength is (0.06)(1^2) = 0.06.
- The total ionic strength of the given solution is 0.09 + 0.07 + 0.06 + 0.06 = 0.28.
2. Solution (a): 0.09 M NaCl
- NaCl dissociates into Na+ and Cl- ions.
- The concentration of Cl- is 0.09 M (from NaCl), and the charge is 1.
- The ionic strength of solution (a) is (0.09)(1^2) = 0.09.
3. Solution (b): 0.04 M Na2SO4
- Na2SO4 dissociates into 2 Na+ and 1 SO4^2- ions.
- The concentration of Na+ is 0.04 M (from Na2SO4), and the charge is 1.
- The concentration of SO4^2- is 0.04 M (from Na2SO4), and the charge is 2.
- The ionic strength of solution (b) is (0.04)(1^2) + (0.04)(2^2) = 0.04 + 0.16 = 0.20.
4. Solution (c): 0.06 M CuSO4
- CuSO4 dissociates into Cu^2+ and SO4^2- ions.
- The concentration of Cu^2+ is 0.06 M (
To determine which solution has the same ionic strength as the given solution, we need to calculate the total ionic strength of each solution and compare.
Definition:
Ionic strength is a measure of the concentration of ions in a solution. It is calculated by summing the products of the concentration of each ion and the square of its charge.
Calculating the ionic strength:
1. Given solution: 0.01 M FeCl3 + 0.06 M HClO4
- FeCl3 dissociates into Fe3+ and 3 Cl- ions.
- HClO4 dissociates into H+ and ClO4- ions.
- The ionic strength is calculated by multiplying the concentration of each ion by the square of its charge.
- For Fe3+, the concentration is 0.01 M and the charge is 3, so the contribution to the ionic strength is (0.01)(3^2) = 0.09.
- For Cl-, the concentration is 0.01 M (from FeCl3) + 0.06 M (from HClO4) = 0.07 M, and the charge is 1, so the contribution to the ionic strength is (0.07)(1^2) = 0.07.
- For H+, the concentration is 0.06 M (from HClO4) and the charge is 1, so the contribution to the ionic strength is (0.06)(1^2) = 0.06.
- For ClO4-, the concentration is 0.06 M (from HClO4) and the charge is 1, so the contribution to the ionic strength is (0.06)(1^2) = 0.06.
- The total ionic strength of the given solution is 0.09 + 0.07 + 0.06 + 0.06 = 0.28.
2. Solution (a): 0.09 M NaCl
- NaCl dissociates into Na+ and Cl- ions.
- The concentration of Cl- is 0.09 M (from NaCl), and the charge is 1.
- The ionic strength of solution (a) is (0.09)(1^2) = 0.09.
3. Solution (b): 0.04 M Na2SO4
- Na2SO4 dissociates into 2 Na+ and 1 SO4^2- ions.
- The concentration of Na+ is 0.04 M (from Na2SO4), and the charge is 1.
- The concentration of SO4^2- is 0.04 M (from Na2SO4), and the charge is 2.
- The ionic strength of solution (b) is (0.04)(1^2) + (0.04)(2^2) = 0.04 + 0.16 = 0.20.
4. Solution (c): 0.06 M CuSO4
- CuSO4 dissociates into Cu^2+ and SO4^2- ions.
- The concentration of Cu^2+ is 0.06 M (
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An aqueous solution containing 0.01 M FeCl3 and 0.06 M HClO4 has the same ionic strength as a solution of:a)0.09 M NaClb)0.04 M Na2SO4c)0.06 M CuSO4d)0.03 M H3PO4Correct answer is option 'B'. Can you explain this answer?
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