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When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed, then the acceleration of the particle is
- a)F1/m
- b)(F2 − F3) m
- c)(F2 F3)/mF1
- d)F2 /m
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
When forces F1, F2, F3 are acting on a particle of mass m such that F2...
The particle remains stationary on the application of three forces that means the resultant force is 0.
This implies
F1 = - (F2 + F3)
Since, if the force F1 is removed, the forces acting are F2 and F3, the resultant of which has the magnitude of F1.
Therefore, the acceleration of the particle is F1 /m
This implies
F1 = - (F2 + F3)
Since, if the force F1 is removed, the forces acting are F2 and F3, the resultant of which has the magnitude of F1.
Therefore, the acceleration of the particle is F1 /m
Most Upvoted Answer
When forces F1, F2, F3 are acting on a particle of mass m such that F2...
Since the particle remains stationary when F1, F2, and F3 are acting on it, the net force on the particle is zero. Therefore,
F1 + F2 + F3 = 0
Since F2 and F3 are mutually perpendicular, we can use Pythagoras theorem to find the magnitude of their resultant force:
|F2 + F3| = √(F2² + F3²)
Now, if we remove F1, the net force on the particle becomes:
F2 + F3
And the acceleration of the particle is given by:
a = (F2 + F3) / m
So the correct answer is (b) F2 + F3 / m.
F1 + F2 + F3 = 0
Since F2 and F3 are mutually perpendicular, we can use Pythagoras theorem to find the magnitude of their resultant force:
|F2 + F3| = √(F2² + F3²)
Now, if we remove F1, the net force on the particle becomes:
F2 + F3
And the acceleration of the particle is given by:
a = (F2 + F3) / m
So the correct answer is (b) F2 + F3 / m.
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When forces F1, F2, F3 are acting on a particle of mass m such that F2...
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When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed, then the acceleration of the particle isa)F1/mb)(F2 − F3) mc)(F2 F3)/mF1d)F2 /mCorrect answer is option 'A'. Can you explain this answer?
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