To calculate the induced emf in the conductor, we can use Faraday's law of electromagnetic induction. According to Faraday's law, the induced emf is equal to the rate of change of magnetic flux through the conductor.

The equation for the induced emf is given by:

emf = -N * dΦ/dt

Where:
emf is the induced electromotive force (emf)
N is the number of turns in the conductor
dΦ/dt is the rate of change of magnetic flux through the conductor

In this case, the conductor is moving through a magnetic field, so the magnetic flux through the conductor is changing. The magnetic flux through the conductor is given by:

Φ = B * A

Where:
B is the magnetic field strength
A is the area of the conductor perpendicular to the magnetic field

Since the conductor is moving perpendicular to the magnetic field, the area of the conductor perpendicular to the magnetic field remains constant. Therefore, the rate of change of magnetic flux is equal to the product of the magnetic field strength and the velocity of the conductor.

dΦ/dt = B * v

Substituting this into the equation for the induced emf, we have:

emf = -N * (B * v)

Given that the conductor is 0.2m long, the velocity is 0.3m/s, and the magnetic field is 5T, we can calculate the induced emf as follows:

emf = -N * (B * v)
= -N * (5T * 0.3m/s)
= -N * 1.5V

Since the question does not provide the number of turns (N) in the conductor, we cannot determine the exact magnitude of the induced emf. However, we can conclude that the emf induced is 0.3V (option A) because the negative sign indicates the direction of the induced current, not the magnitude of the emf.