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A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer?.

Solutions for A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.

Here you can find the meaning of A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A uniformly doped npn bipolar transistor has following parameters:NE = 1018 cm-3 NB = 5 x 1016 cm-3,Nc= 2 x 1019 cm-3,DE = 8 cm2/s , DB = 15 cm2 /s , Dc= 14 cm2 /sxE = 0.8 μm, xB= 0.7 μmThe emitter injection efficiency γ isa)0.999b)0.977c)0.982d)0.934Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.