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A bipolar transistor has an emitter current of 1 mA. The emitter injection efficiency is 0.99, base transit factor is 0.995 and depletion region recombination factor of 0.998. The base current flowing through the transistor is _____μA.
    Correct answer is between '16,18'. Can you explain this answer?
    Verified Answer
    A bipolar transistor has an emitter current of 1 mA. The emitter injec...
    The common emitter current gain is given by:
    α = γ ∗ β ∗ δ
    = 0.99 × 0.995 × 0.998 = 0.983
    Collector current
    Ic = αIE = 0.983 mA
    Base current
    IB = IE – IC
    = 17 μA 
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    Most Upvoted Answer
    A bipolar transistor has an emitter current of 1 mA. The emitter injec...
    To find the base current flowing through the transistor, we can use the formula:

    Emitter current (Ie) = Base current (Ib) + Collector current (Ic)

    Given that the emitter current (Ie) is 1 mA, we can substitute this value into the formula:

    1 mA = Ib + Ic

    We also know that the emitter injection efficiency (η) is 0.99, the base transit factor (α) is 0.995, and the depletion region recombination factor (β) is 0.998.

    The emitter injection efficiency (η) is defined as the ratio of the number of carriers injected into the base to the total number of carriers crossing the emitter-base junction. This can be written as:

    η = Ie / (Ie + Ic)

    Substituting the given values, we have:

    0.99 = 1 mA / (1 mA + Ic)

    Rearranging the equation, we can solve for Ic:

    Ic = (1 mA / 0.99) - 1 mA

    Ic ≈ 0.01 mA

    The base transit factor (α) is defined as the ratio of the collector current (Ic) to the emitter current (Ie). This can be written as:

    α = Ic / Ie

    Substituting the given values, we have:

    0.995 = 0.01 mA / 1 mA

    Simplifying the equation, we find:

    0.995 = 0.01

    This equation is not true, so there must be an error in the given values.

    Without the correct values for the base transit factor (α) and the depletion region recombination factor (β), we cannot accurately calculate the base current (Ib) flowing through the transistor.
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    A bipolar transistor has an emitter current of 1 mA. The emitter injection efficiency is 0.99, base transit factor is 0.995 and depletion region recombination factor of 0.998. The base current flowing through the transistor is _____μA.Correct answer is between '16,18'. Can you explain this answer?
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    A bipolar transistor has an emitter current of 1 mA. The emitter injection efficiency is 0.99, base transit factor is 0.995 and depletion region recombination factor of 0.998. The base current flowing through the transistor is _____μA.Correct answer is between '16,18'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A bipolar transistor has an emitter current of 1 mA. The emitter injection efficiency is 0.99, base transit factor is 0.995 and depletion region recombination factor of 0.998. The base current flowing through the transistor is _____μA.Correct answer is between '16,18'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bipolar transistor has an emitter current of 1 mA. The emitter injection efficiency is 0.99, base transit factor is 0.995 and depletion region recombination factor of 0.998. The base current flowing through the transistor is _____μA.Correct answer is between '16,18'. Can you explain this answer?.
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