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A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:
- a)0.015
- b)0.045
- c)0.030
- d)0.225
Correct answer is option 'B'. Can you explain this answer?
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A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichroma...
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To determine the molarity of the Na2SO3 solution, we can use the concept of stoichiometry and the given volume and concentration of the potassium dichromate solution.
The balanced chemical equation for the oxidation of Na2SO3 to Na2SO4 by potassium dichromate is:
3 Na2SO3 + K2Cr2O7 + 4 H2SO4 → 3 Na2SO4 + Cr2(SO4)3 + K2SO4 + 4 H2O
From the equation, we can see that the ratio of Na2SO3 to K2Cr2O7 is 3:1. This means that for every 3 moles of Na2SO3, 1 mole of K2Cr2O7 is required for complete oxidation.
Let's calculate the moles of K2Cr2O7 used in the reaction:
moles of K2Cr2O7 = volume (in L) × concentration (in M)
= 30 mL × 0.01 M
= 0.03 mol
Since the ratio of Na2SO3 to K2Cr2O7 is 3:1, the moles of Na2SO3 would be three times that of K2Cr2O7:
moles of Na2SO3 = 3 × moles of K2Cr2O7
= 3 × 0.03 mol
= 0.09 mol
Now, we can calculate the molarity of the Na2SO3 solution:
molarity = moles of Na2SO3 / volume of Na2SO3 solution (in L)
= 0.09 mol / 0.02 L
= 4.5 M
Hence, the molarity of the Na2SO3 solution is 4.5 M.
Therefore, the correct answer is option B) 0.045 M.
The balanced chemical equation for the oxidation of Na2SO3 to Na2SO4 by potassium dichromate is:
3 Na2SO3 + K2Cr2O7 + 4 H2SO4 → 3 Na2SO4 + Cr2(SO4)3 + K2SO4 + 4 H2O
From the equation, we can see that the ratio of Na2SO3 to K2Cr2O7 is 3:1. This means that for every 3 moles of Na2SO3, 1 mole of K2Cr2O7 is required for complete oxidation.
Let's calculate the moles of K2Cr2O7 used in the reaction:
moles of K2Cr2O7 = volume (in L) × concentration (in M)
= 30 mL × 0.01 M
= 0.03 mol
Since the ratio of Na2SO3 to K2Cr2O7 is 3:1, the moles of Na2SO3 would be three times that of K2Cr2O7:
moles of Na2SO3 = 3 × moles of K2Cr2O7
= 3 × 0.03 mol
= 0.09 mol
Now, we can calculate the molarity of the Na2SO3 solution:
molarity = moles of Na2SO3 / volume of Na2SO3 solution (in L)
= 0.09 mol / 0.02 L
= 4.5 M
Hence, the molarity of the Na2SO3 solution is 4.5 M.
Therefore, the correct answer is option B) 0.045 M.
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A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:a)0.015b)0.045c)0.030d)0.225Correct answer is option 'B'. Can you explain this answer?
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A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:a)0.015b)0.045c)0.030d)0.225Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:a)0.015b)0.045c)0.030d)0.225Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:a)0.015b)0.045c)0.030d)0.225Correct answer is option 'B'. Can you explain this answer?.
A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:a)0.015b)0.045c)0.030d)0.225Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:a)0.015b)0.045c)0.030d)0.225Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 20 mL solution of Na2SO3 required 30 mL of 0.01 M Potassium dichromate solution for oxidation to Na2SO4. Hence, Molarity of Na2SO3 solution is:a)0.015b)0.045c)0.030d)0.225Correct answer is option 'B'. Can you explain this answer?.
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