If S is the closed surface enclosing a volume 1m3 andis the unit normal vector to the surface is position vector, then the value of the following integralis ______.Correct answer is '3'. Can you explain this answer?

Question

Answer

According to Gauss's theorem the surface integral of the normal component of a vector function F tapes around a closed surface S is equal to the integral of the divergence of F taken over the volume C(1m³) enclosed by surface.

Similar Physics Doubts

Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder is

Calculate the volume of the surface integral where s is the surface the sphere x2 + y2 + z2 = 4 and n is the unit outward normal to the sphere and Correct answer is '16'. Can you explain this answer?

If the surface integral of the field a (x, y, z) = 2axi byj-3yzk over the closed surface an arbitrary unit sphere is to be zero, then the relationship between a, ß and y is(jam 2016)?

If the surface integral of the field over the closed surface of an arbitrary unit sphere is to be zero, then the relationship between , and is

A cubic block with side a and mass M has 1/4 of its volume floating on the surface of a fluid in the presence of gravity. If the cube sinks a distance a / 10 and is then released, find the vertical position of the center of mass in time.?

Top Courses for Physics

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams