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Consider a cylinder of height h and radius a, closed at both ends, centered at the origin. Let 
the position vector and 
unit vector normal to the surface. The surface integral 
over the closed surface of the cylinder is
the position vector and unit vector normal to the surface. The surface integral over the closed surface of the cylinder is- a)2πa2(a+h)
- b)3πa2h
- c)2πa2h
- d)Zero
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Consider a cylinder of height h and radius a, closed at both ends, cen...
For calculation of surface integral ,we need surface normal 
on the top surface of the cylinder shown in adjacent figure
Where
is the given position vector. Thus
top surface
(on top surface)
On the bottom surface of the cylinder
vector
is normal to the current surface of the cylinder and therefore for this surface we have
Thus
a(area of curved surface) 
The value of
are the whole surface of cylinder is then 
on the top surface of the cylinder shown in adjacent figureWhere
is the given position vector. Thustop surface
(on top surface)On the bottom surface of the cylinder
vector
is normal to the current surface of the cylinder and therefore for this surface we haveThus
a(area of curved surface) The value of
are the whole surface of cylinder is then Most Upvoted Answer
Consider a cylinder of height h and radius a, closed at both ends, cen...
For calculation of surface integral ,we need surface normal 
on the top surface of the cylinder shown in adjacent figure
Where
is the given position vector. Thus
top surface
(on top surface)
On the bottom surface of the cylinder
vector
is normal to the current surface of the cylinder and therefore for this surface we have
Thus
a(area of curved surface) 
The value of
are the whole surface of cylinder is then 
on the top surface of the cylinder shown in adjacent figureWhere
is the given position vector. Thustop surface
(on top surface)On the bottom surface of the cylinder
vector
is normal to the current surface of the cylinder and therefore for this surface we haveThus
a(area of curved surface) The value of
are the whole surface of cylinder is then
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Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer?
Question Description
Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer?.
Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
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Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Consider a cylinder of height h and radius a, closed at both ends, centered atthe origin. Letthe position vector andunit vector normal to the surface. The surface integralover the closed surface of the cylinder isa)2πa2(a+h)b)3πa2hc)2πa2hd)ZeroCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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