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A voltage source VAB = 4 sin ωt is applied to the terminals A & B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminals A & B is:-
  • a)
    5kΩ
  • b)
    10kΩ
  • c)
    20kΩ
  • d)
    15kΩ
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A voltage source VAB = 4 sin ωt is applied to the terminals A &a...
Diode D1 conducts through 10 kΩ on the extreme right & Diode D2 conduct through the 10 kΩ in the middle branch Diode D1 is blocked.
Then the source always sees a resistance of 10kΩ..
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Most Upvoted Answer
A voltage source VAB = 4 sin ωt is applied to the terminals A &a...
Diode D1 conducts through 10 kΩ on the extreme right & Diode D2 conduct through the 10 kΩ in the middle branch Diode D1 is blocked.
Then the source always sees a resistance of 10kΩ..
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A voltage source VAB = 4 sin ωt is applied to the terminals A & B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminals A & B is:-a)5kΩb)10kΩc)20kΩd)15kΩCorrect answer is option 'B'. Can you explain this answer?
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