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A voltage source VAB = 4 sin ωt is applied to the terminal A and B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminal A and B is __________ kΩ.
    Correct answer is '10'. Can you explain this answer?
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    A voltage source VAB = 4 sin ωt is applied to the terminal A and...
    Diode D1 conducts through 10 kΩ on the extreme right and diode D2 is blocked. Diode D2, conducts through the 10k Ω in the middle branch and diode D1 is blocked. Thus the source always sees a resistance of 10 kΩ.
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    A voltage source VAB = 4 sin ωt is applied to the terminal A and B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminal A and B is __________ kΩ.Correct answer is '10'. Can you explain this answer?
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    A voltage source VAB = 4 sin ωt is applied to the terminal A and B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminal A and B is __________ kΩ.Correct answer is '10'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A voltage source VAB = 4 sin ωt is applied to the terminal A and B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminal A and B is __________ kΩ.Correct answer is '10'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A voltage source VAB = 4 sin ωt is applied to the terminal A and B of the circuit shown in the given figure. The diodes are assumed to be ideal. The impedance by the circuit across the terminal A and B is __________ kΩ.Correct answer is '10'. Can you explain this answer?.
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