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A body falls freely from a tower and travels a distance of 40m in its last two seconds.Then find the height of the tower.?
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A body falls freely from a tower and travels a distance of 40m in its ...
We will have to use the third equation , h=ut+1/2gt^2

u=0 m/s

g=10 m/s^2

t=2 sec

h=?

h=ut+1/2at^2

or, h=0×2+1/2×10×2×2

or, h=0+5×4

or, h=20 m

so, the height of the tower is 20 m
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A body falls freely from a tower and travels a distance of 40m in its last two seconds.Then find the height of the tower.?
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