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In given figure a silicon diode is carrying a constant current of 1 mA. When the temperature of the diode is 20ºC, VD is found to be 700 mV. If the temperature rises to 40ºC, VD becomes approximately equal to
  • a)
    747 mV
  • b)
    660 mV
  • c)
    680 mV
  • d)
    700 mV
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In given figure a silicon diode is carrying a constant current of 1 mA...
Id = Io(eVD/ηVT - 1)
By considering , then
= eVD/ηVT
Id is constant according to question,
VD a T
.
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In given figure a silicon diode is carrying a constant current of 1 mA. When the temperature of the diode is 20ºC, VD is found to be 700 mV. If the temperature rises to 40ºC, VD becomes approximately equal toa)747 mVb)660 mVc)680 mVd)700 mVCorrect answer is option 'A'. Can you explain this answer?
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