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50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)
- a)5°C
- b)6°C
- c)7°C
- d)8°C
Correct answer is option 'A'. Can you explain this answer?
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50g of copper is heated to increase its temperature by 10°C. If th...
Same amount of heat is supplied to copper and water, so
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50g of copper is heated to increase its temperature by 10°C. If th...
To calculate the increase in temperature of the copper, we need to know the specific heat capacity of copper. The specific heat capacity of copper is approximately 0.385 J/g°C.
The formula to calculate the change in temperature is:
Change in temperature (ΔT) = (heat energy gained) / (mass x specific heat capacity)
Given:
Mass (m) = 50 g
Specific heat capacity (c) = 0.385 J/g°C
Heat energy gained = mass x specific heat capacity x change in temperature
We want to calculate the change in temperature when the heat energy gained is known.
Rearranging the formula, we get:
Change in temperature (ΔT) = (heat energy gained) / (mass x specific heat capacity)
Substituting the given values into the formula:
Change in temperature (ΔT) = (heat energy gained) / (50 g x 0.385 J/g°C)
Now, let's assume the heat energy gained is 10 J.
Change in temperature (ΔT) = 10 J / (50 g x 0.385 J/g°C)
Calculating the change in temperature:
ΔT = 10 J / (19.25 J/°C)
ΔT = 0.52 °C
Therefore, heating 50g of copper with 10 J of heat energy will increase its temperature by approximately 0.52 °C.
The formula to calculate the change in temperature is:
Change in temperature (ΔT) = (heat energy gained) / (mass x specific heat capacity)
Given:
Mass (m) = 50 g
Specific heat capacity (c) = 0.385 J/g°C
Heat energy gained = mass x specific heat capacity x change in temperature
We want to calculate the change in temperature when the heat energy gained is known.
Rearranging the formula, we get:
Change in temperature (ΔT) = (heat energy gained) / (mass x specific heat capacity)
Substituting the given values into the formula:
Change in temperature (ΔT) = (heat energy gained) / (50 g x 0.385 J/g°C)
Now, let's assume the heat energy gained is 10 J.
Change in temperature (ΔT) = 10 J / (50 g x 0.385 J/g°C)
Calculating the change in temperature:
ΔT = 10 J / (19.25 J/°C)
ΔT = 0.52 °C
Therefore, heating 50g of copper with 10 J of heat energy will increase its temperature by approximately 0.52 °C.
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50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)a)5°Cb)6°Cc)7°Cd)8°CCorrect answer is option 'A'. Can you explain this answer?
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50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)a)5°Cb)6°Cc)7°Cd)8°CCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)a)5°Cb)6°Cc)7°Cd)8°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)a)5°Cb)6°Cc)7°Cd)8°CCorrect answer is option 'A'. Can you explain this answer?.
50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)a)5°Cb)6°Cc)7°Cd)8°CCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)a)5°Cb)6°Cc)7°Cd)8°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50g of copper is heated to increase its temperature by 10°C. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper = 420J/kg °C, specific heat of water = 4200 J/kg °C)a)5°Cb)6°Cc)7°Cd)8°CCorrect answer is option 'A'. Can you explain this answer?.
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