CA Foundation Exam > CA Foundation Questions > If u/v = w/p, then (u–v)/(u+v) = (wR...
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If u/v = w/p, then (u–v)/(u+v) = (w–p)/(w+p). The process is called
- a)Invertendo
- b)Alternendo
- c)Addendo
- d)none of these
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If u/v = w/p, then (u–v)/(u+v) = (w–p)/(w+p). The process ...
Given, u/v = w/p
To prove: (uv)/(u v) = (wp)/(w p)
Explanation:
- Let's start by simplifying the left-hand side of the equation:
(uv)/(uv) = 1
- Now, let's simplify the right-hand side of the equation:
(wp)/(wp) = 1
- Therefore, we can see that both sides of the equation are equal to 1, which means that the equation is true.
Answer: None of these (Option D)
To prove: (uv)/(u v) = (wp)/(w p)
Explanation:
- Let's start by simplifying the left-hand side of the equation:
(uv)/(uv) = 1
- Now, let's simplify the right-hand side of the equation:
(wp)/(wp) = 1
- Therefore, we can see that both sides of the equation are equal to 1, which means that the equation is true.
Answer: None of these (Option D)
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Community Answer
If u/v = w/p, then (u–v)/(u+v) = (w–p)/(w+p). The process ...
U/v=w/p
u/v+1=w/p+1
u+v/v=w+p/p. _(1)(componendo)
u/v=w/p
u/v-1=w/p-1
u-v/v=w-p/p_(2)(dividendo)
(2)/(1) we get
u-v/u+v=w-p/w+p. (componendo and dividendo)
u/v+1=w/p+1
u+v/v=w+p/p. _(1)(componendo)
u/v=w/p
u/v-1=w/p-1
u-v/v=w-p/p_(2)(dividendo)
(2)/(1) we get
u-v/u+v=w-p/w+p. (componendo and dividendo)
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