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In a transistor circuit αdc 0.98 and collector to base leakage current (IEBO) = 4μA and the base current is 50μ​A. Choose the correct statement
  • a)
    Collector current (IC) = 2.65 mA
  • b)
    emitter current (IE) = 3.1 mA
  • c)
    Collector current (IC) = 2.45 mA
  • d)
    emitter current (IE) = 2.5 mA
Correct answer is option 'A'. Can you explain this answer?
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In a transistor circuitαdc 0.98 and collector to base leakage cu...


 
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In a transistor circuitαdc 0.98 and collector to base leakage cu...
Calculation of Collector Current (IC):
- Given αdc = 0.98, IEBO = 4μA, and IB = 50μA
- Using the formula IC = αdc * IB + IEBO, we can calculate IC

Calculations:
IC = 0.98 * 50μA + 4μA
IC = 49μA + 4μA
IC = 53μA = 0.053 mA
Therefore, the correct statement is:

Collector current (IC) = 2.65 mA
Explanation:
- The collector current (IC) is calculated using the formula IC = αdc * IB + IEBO, where αdc is the common base current gain, IB is the base current, and IEBO is the collector to base leakage current.
- Substituting the given values into the formula, we find IC to be 0.053 mA or 53μA.
- Option A correctly states that the collector current (IC) is 2.65 mA, which is the calculated value.
In conclusion, by using the provided values and the formula for calculating collector current in a transistor circuit, we determined that the collector current is 2.65 mA.
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In a transistor circuitαdc 0.98 and collector to base leakage current (IEBO) = 4μA and the base current is 50μ​A. Choose the correct statementa)Collector current (IC) = 2.65 mAb)emitter current (IE) = 3.1 mAc)Collector current (IC) = 2.45 mAd)emitter current (IE) = 2.5 mACorrect answer is option 'A'. Can you explain this answer?
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