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For a BJT, the current amplification factor ∝ = 0.9 . This transistor is connected in common emitter configurations. When the base current changes by 0.4 mA, the change in collector current will be (in mA).
Correct answer is '3.6'. Can you explain this answer?
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For a BJT, the current amplification factor ∝ = 0.9 . This transi...
The correct answer is: 3.6
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For a BJT, the current amplification factor ∝ = 0.9 . This transi...
Understanding BJT Current Amplification
In a Bipolar Junction Transistor (BJT) configured in a common emitter mode, the current amplification factor (also known as beta, β) indicates how much the collector current (Ic) is amplified compared to the base current (Ib).
Given Parameters
- Current amplification factor (β) = 0.9
- Change in base current (ΔIb) = 0.4 mA
Calculating Change in Collector Current
The relationship between the changes in base current and collector current is expressed as:
- ΔIc = β × ΔIb
By substituting the known values:
- ΔIc = 0.9 × 0.4 mA
Performing the Calculation
- ΔIc = 0.36 mA
This value represents the change in the collector current corresponding to the change in base current.
Understanding the Result
However, the question states that the correct answer is '3.6 mA'. This can occur if the value of β is misinterpreted.
Correct Interpretation
If we consider that the amplification factor is intended to represent a factor of 10 instead of 0.9, we recalculate:
- ΔIc = 10 × ΔIb
- ΔIc = 10 × 0.4 mA = 4 mA
This indicates a common miscommunication regarding the amplification factor's interpretation.
To summarize, the change in collector current when the base current changes by 0.4 mA is:
- If β = 0.9: ΔIc = 0.36 mA
- If β is misinterpreted as 9: ΔIc = 3.6 mA
Understanding the amplification factor is crucial for accurate calculations in BJT circuits.
In a Bipolar Junction Transistor (BJT) configured in a common emitter mode, the current amplification factor (also known as beta, β) indicates how much the collector current (Ic) is amplified compared to the base current (Ib).
Given Parameters
- Current amplification factor (β) = 0.9
- Change in base current (ΔIb) = 0.4 mA
Calculating Change in Collector Current
The relationship between the changes in base current and collector current is expressed as:
- ΔIc = β × ΔIb
By substituting the known values:
- ΔIc = 0.9 × 0.4 mA
Performing the Calculation
- ΔIc = 0.36 mA
This value represents the change in the collector current corresponding to the change in base current.
Understanding the Result
However, the question states that the correct answer is '3.6 mA'. This can occur if the value of β is misinterpreted.
Correct Interpretation
If we consider that the amplification factor is intended to represent a factor of 10 instead of 0.9, we recalculate:
- ΔIc = 10 × ΔIb
- ΔIc = 10 × 0.4 mA = 4 mA
This indicates a common miscommunication regarding the amplification factor's interpretation.
To summarize, the change in collector current when the base current changes by 0.4 mA is:
- If β = 0.9: ΔIc = 0.36 mA
- If β is misinterpreted as 9: ΔIc = 3.6 mA
Understanding the amplification factor is crucial for accurate calculations in BJT circuits.
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For a BJT, the current amplification factor ∝ = 0.9 . This transi...
The correct answer is: 3.6
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For a BJT, the current amplification factor ∝ = 0.9 . This transistor is connected in common emitter configurations. When the base current changes by 0.4 mA, the change in collector current will be (in mA).Correct answer is '3.6'. Can you explain this answer?
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