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A slope is to be constructed at an angle of 300 to the horizontal from a soil having properties, e = 20 kN/ m2, φ = 300, γ= 19 kN/m3. Taylor’s stability numbers is 0.05. If the factor of safety of 1.5 is required, then the safe height of the slope (in m) will be______
(Important - Enter only the numerical value in the answer)
    Correct answer is '14.04'. Can you explain this answer?
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    - **Given Parameters**
    The given parameters are:
    - e = 20 kN/m2
    - φ = 30°
    - γ = 19 kN/m3
    - Taylor’s stability number = 0.05
    - Factor of safety = 1.5
    - **Calculations**
    Using the Taylor's stability number formula:
    \[ FS = \frac{e + γH \tan\phi;}{γH} \]
    Substitute the given values and rearrange the formula to solve for the height (H):
    \[ 1.5 = \frac{20 + 19H \tan30°}{19H} \]
    \[ H = \frac{20}{19(1.5 - \tan30°)} \]
    \[ H ≈ 14.04 m \]
    - **Conclusion**
    Therefore, the safe height of the slope should be approximately 14.04 meters to achieve a factor of safety of 1.5.
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    A slope is to be constructed at anangle of 300 to the horizontal froma soil having properties, e = 20 kN/m2, φ = 300, γ= 19 kN/m3. Taylor’sstability numbers is 0.05. If thefactor of safety of 1.5 is required,then the safe height of the slope (inm) will be______(Important - Enter only the numerical value in the answer)Correct answer is '14.04'. Can you explain this answer?
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