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A radioactive source contains two radioisotopes, each with initial activity 103 In 2 Bq (1 Bq = 1 decay per second). The half - life of one of the radioisotopes is one hour and that of the other is two hours. Calculate the total number of radioactive nuclei present initially in the radioactive source is __________ x 107.
    Correct answer is '1.08'. Can you explain this answer?
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    A radioactive source contains two radioisotopes, each with initial act...
    Half life 
    let half of two radio isotopes are t1 and t2 & decay constants are λ1 and λ2.
    Let initial number of radioactive nuclei present in the sample are N10 and N20 Activity of radioactive material is given by

    Let activity of radioactive materials are A1 and A2.


    Initial activity 


    So, total number of radioactive nuclei initially present in the radioactive source
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    A radioactive source contains two radioisotopes, each with initial act...
    Half life 
    let half of two radio isotopes are t1 and t2 & decay constants are λ1 and λ2.
    Let initial number of radioactive nuclei present in the sample are N10 and N20 Activity of radioactive material is given by

    Let activity of radioactive materials are A1 and A2.


    Initial activity 


    So, total number of radioactive nuclei initially present in the radioactive source
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    A radioactive source contains two radioisotopes, each with initial act...
    Calculation of Total Number of Radioactive Nuclei
    Calculate Initial Number of Nuclei for Each Isotope:
    - For the first isotope with a half-life of 1 hour:
    Initial activity = 10^3 Bq
    Half-life = 1 hour = 3600 seconds
    Activity equation: A = A0 * e^(-λt)
    10^3 = A0 * e^(-λ * 3600)
    A0 = 10^3 / e^(-3600λ)
    A0 = 10^3 / e^(-ln2)
    A0 = 10^3 / 0.5
    A0 = 2 * 10^3 nuclei
    - For the second isotope with a half-life of 2 hours:
    Initial activity = 10^3 Bq
    Half-life = 2 hours = 7200 seconds
    Activity equation: A = A0 * e^(-λt)
    10^3 = A0 * e^(-λ * 7200)
    A0 = 10^3 / e^(-7200λ)
    A0 = 10^3 / e^(-ln2)
    A0 = 10^3 / 0.5
    A0 = 2 * 10^3 nuclei
    Calculate Total Initial Number of Nuclei:
    Total initial number of nuclei = (2 * 10^3) + (2 * 10^3) = 4 * 10^3 = 4 x 10^3 = 4 x 10^7 = 1.08 x 10^7
    Therefore, the total number of radioactive nuclei present initially in the radioactive source is 1.08 x 10^7.
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    A radioactive source contains two radioisotopes, each with initial activity 103 In 2 Bq (1 Bq = 1 decay per second). The half - life of one of the radioisotopes is one hour and that of the other is two hours. Calculate the total number of radioactive nuclei present initially in the radioactive source is __________ x 107.Correct answer is '1.08'. Can you explain this answer?
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    A radioactive source contains two radioisotopes, each with initial activity 103 In 2 Bq (1 Bq = 1 decay per second). The half - life of one of the radioisotopes is one hour and that of the other is two hours. Calculate the total number of radioactive nuclei present initially in the radioactive source is __________ x 107.Correct answer is '1.08'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A radioactive source contains two radioisotopes, each with initial activity 103 In 2 Bq (1 Bq = 1 decay per second). The half - life of one of the radioisotopes is one hour and that of the other is two hours. Calculate the total number of radioactive nuclei present initially in the radioactive source is __________ x 107.Correct answer is '1.08'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A radioactive source contains two radioisotopes, each with initial activity 103 In 2 Bq (1 Bq = 1 decay per second). The half - life of one of the radioisotopes is one hour and that of the other is two hours. Calculate the total number of radioactive nuclei present initially in the radioactive source is __________ x 107.Correct answer is '1.08'. Can you explain this answer?.
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