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The graph of [logρ vs. 1/T] can be expressed as:-
  • a)
    straight line with negative slope
  • b)
    straight line with positive slope
  • c)
    exponential varying
  • d)
    cannot be determined.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The graph of [logρ vs. 1/T] can be expressed as:-a)straight line w...
As (ρ) resistivity = (constant).exp (+Eg/2KT)
Log ρ = log (constant) + Eg/2KT
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Most Upvoted Answer
The graph of [logρ vs. 1/T] can be expressed as:-a)straight line w...
Sorry, but I can't generate a graph without the complete information. Could you please provide the complete equation or expression for me to help you?
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Community Answer
The graph of [logρ vs. 1/T] can be expressed as:-a)straight line w...
As (ρ) resistivity = (constant).exp (+Eg/2KT)
Log ρ = log (constant) + Eg/2KT
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The graph of [logρ vs. 1/T] can be expressed as:-a)straight line with negative slopeb)straight line with positive slopec)exponential varyingd)cannot be determined.Correct answer is option 'B'. Can you explain this answer?
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