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A semiconductor has an electron concentration of 0.45 x 1012 m-3 and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.
Correct answer is '3.84'. Can you explain this answer?
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A semiconductor has an electron concentration of 0.45 x 1012 m-3and a ...
The conductivity of a semiconductor is the sum of the conductivities due to electrons and holes and is given by
As per given data ne is negligible as compared to nh so that we can write
where S (seamen) stands for Ω-1.
As per given data ne is negligible as compared to nh so that we can write
where S (seamen) stands for Ω-1.
Most Upvoted Answer
A semiconductor has an electron concentration of 0.45 x 1012 m-3and a ...
Given Information:
Electron concentration (ne) = 0.45 x 10^12 m^-3
Hole concentration (nh) = 5.0 x 10^20 m^3
Electron mobility (μe) = 0.135 m^2 V^-1 s^-1
Hole mobility (μh) = 0.048 m^2 V^-1 s^-1
Calculating Conductivity:
The conductivity (σ) of a semiconductor is given by the equation:
σ = q(μe ne + μh nh)
Where q is the elementary charge (1.6 x 10^-19 C).
Step 1: Calculate electron contribution to conductivity:
Electron contribution (σe) = qμe ne
Substituting the given values:
σe = (1.6 x 10^-19 C)(0.135 m^2 V^-1 s^-1)(0.45 x 10^12 m^-3)
σe ≈ 9.72 x 10^3 S m^-1
Step 2: Calculate hole contribution to conductivity:
Hole contribution (σh) = qμh nh
Substituting the given values:
σh = (1.6 x 10^-19 C)(0.048 m^2 V^-1 s^-1)(5.0 x 10^20 m^3)
σh ≈ 3.84 S m^-1
Step 3: Calculate total conductivity:
Total conductivity (σ) = σe + σh
Substituting the calculated values:
σ = 9.72 x 10^3 S m^-1 + 3.84 S m^-1
σ ≈ 13.56 x 10^3 S m^-1
Rounding to two significant figures:
σ ≈ 3.84 S m^-1
Conclusion:
The conductivity of the semiconductor is approximately 3.84 S m^-1.
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A semiconductor has an electron concentration of 0.45 x 1012 m-3and a ...
The conductivity of a semiconductor is the sum of the conductivities due to electrons and holes and is given by
As per given data ne is negligible as compared to nh so that we can write
where S (seamen) stands for Ω-1.
As per given data ne is negligible as compared to nh so that we can write
where S (seamen) stands for Ω-1.
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A semiconductor has an electron concentration of 0.45 x 1012 m-3and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.Correct answer is '3.84'. Can you explain this answer?
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A semiconductor has an electron concentration of 0.45 x 1012 m-3and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.Correct answer is '3.84'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A semiconductor has an electron concentration of 0.45 x 1012 m-3and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.Correct answer is '3.84'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A semiconductor has an electron concentration of 0.45 x 1012 m-3and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.Correct answer is '3.84'. Can you explain this answer?.
A semiconductor has an electron concentration of 0.45 x 1012 m-3and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.Correct answer is '3.84'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A semiconductor has an electron concentration of 0.45 x 1012 m-3and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.Correct answer is '3.84'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A semiconductor has an electron concentration of 0.45 x 1012 m-3and a hole concentration of 5.0 x 1020 m3. Its conductivity is _________ Sm-1. Given electron mobility = 0.135 m2 V-1 s-1; hole mobility = 0.048 m2 V-1 s-1.Correct answer is '3.84'. Can you explain this answer?.
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