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A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)
Correct answer is '3.84'. Can you explain this answer?
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A semiconductor has an electron concentratiion of 0.45 x 1012m-3 &...
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Calculation of Conductivity of Semiconductor
The conductivity of a semiconductor can be calculated using the formula:
σ = q * (n * μn + p * μp)
Where:
σ = conductivity
q = charge of an electron (1.6 x 10^-19 C)
n = electron concentration (0.45 x 10^12 m^-3)
μn = electron mobility (0.135 m^2V^-1S^-1)
p = hole concentration (5.0 x 10^20 m^-3)
μp = hole mobility (0.048 m^2V^-1S^-1)
Calculation
1. Calculate the contribution of electrons to conductivity:
n * μn = 0.45 x 10^12 * 0.135 = 6.075 x 10^10
2. Calculate the contribution of holes to conductivity:
p * μp = 5.0 x 10^20 * 0.048 = 2.4 x 10^19
3. Calculate the total conductivity:
σ = 1.6 x 10^-19 * (6.075 x 10^10 + 2.4 x 10^19) = 3.84
Therefore, the conductivity of the semiconductor is 3.84 in SI units.
The conductivity of a semiconductor can be calculated using the formula:
σ = q * (n * μn + p * μp)
Where:
σ = conductivity
q = charge of an electron (1.6 x 10^-19 C)
n = electron concentration (0.45 x 10^12 m^-3)
μn = electron mobility (0.135 m^2V^-1S^-1)
p = hole concentration (5.0 x 10^20 m^-3)
μp = hole mobility (0.048 m^2V^-1S^-1)
Calculation
1. Calculate the contribution of electrons to conductivity:
n * μn = 0.45 x 10^12 * 0.135 = 6.075 x 10^10
2. Calculate the contribution of holes to conductivity:
p * μp = 5.0 x 10^20 * 0.048 = 2.4 x 10^19
3. Calculate the total conductivity:
σ = 1.6 x 10^-19 * (6.075 x 10^10 + 2.4 x 10^19) = 3.84
Therefore, the conductivity of the semiconductor is 3.84 in SI units.
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A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)Correct answer is '3.84'. Can you explain this answer?
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A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)Correct answer is '3.84'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)Correct answer is '3.84'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)Correct answer is '3.84'. Can you explain this answer?.
A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)Correct answer is '3.84'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)Correct answer is '3.84'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A semiconductor has an electron concentratiion of 0.45 x 1012m-3 & a hole concentration of 5.0 x 1020 m-3. Calculate its conductivity (in SI). (Given electron mobility = 0.135 m2V-1S-1 hole mobility = 0.048m2V-1S-1.)Correct answer is '3.84'. Can you explain this answer?.
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