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What will be the value of limiting depth of neutral axis in a singly reinforced beam of section 300mm × 500mm (effective depth), if strain in concrete at limit state of collapse was found to be 0.0030? Use M20 grade of concrete and Fe 415 grade of steel.
  • a)
    180mm
  • b)
    205mm
  • c)
    220mm
  • d)
    240mm
Correct answer is option 'C'. Can you explain this answer?
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What will be the value of limiting depth of neutral axis in a singly r...

d = 500mm
Xulim = 220.70mm
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What will be the value of limiting depth of neutral axis in a singly r...
To determine the limiting depth of the neutral axis in a singly reinforced beam, we need to consider the strain in concrete at the limit state of collapse. The formula used to calculate the limiting depth is given as:

x = (0.87 * h * σ_st) / (0.36 * f_ck)

Where:
x = limiting depth of the neutral axis
h = effective depth of the beam
σ_st = stress in steel
f_ck = characteristic compressive strength of concrete

Given data:
h = effective depth = 300 mm
f_ck = characteristic compressive strength of concrete = M20 grade = 20 N/mm²
σ_st = stress in steel = Fe 415 grade = 415 N/mm²

Substituting the values into the formula:

x = (0.87 * 300 * 415) / (0.36 * 20)

Calculating the value:

x = 220 mm

Therefore, the limiting depth of the neutral axis in the given singly reinforced beam is 220 mm.

- Formula: x = (0.87 * h * σ_st) / (0.36 * f_ck)
- Given data: h = 300 mm, f_ck = 20 N/mm², σ_st = 415 N/mm²
- Substituting the values: x = (0.87 * 300 * 415) / (0.36 * 20)
- Calculating the value: x = 220 mm
- Therefore, the limiting depth of the neutral axis is 220 mm.
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What will be the value of limiting depth of neutral axis in a singly reinforced beam of section 300mm × 500mm (effective depth), if strain in concrete at limit state of collapse was found to be 0.0030? Use M20 grade of concrete and Fe 415 grade of steel.a)180mmb) 205mmc)220mmd) 240mmCorrect answer is option 'C'. Can you explain this answer?
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