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In an A.P, the 12th term is 7 times the 2nd term and the 8th term is 3 more than 10 times the first term. What is the 5th term of the G.P whose first term is the first term of A.P and whose common ratio is equal to the common difference of the A.P.
  • a)
    152
  • b)
    144
  • c)
    156
  • d)
    None of these
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In an A.P, the 12th term is 7 times the 2nd term and the 8th term is 3...
Let the progression be a,a+d,a+2d..................
The 1st line gives us the equation, a+lld=7a+7d = 6a=4d
= 3a=2d------------------ (1)
Also, a+7d = 10a+3 = 7d=9a+3
= 7d=6d+3 from (1), we get 3a=2d, hence 9a = 6d 
^ d=3,a=2
The GP is 2,2x3,2x32,2x33,2x34.
So the 5th term is 162. Hence, d.
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Most Upvoted Answer
In an A.P, the 12th term is 7 times the 2nd term and the 8th term is 3...
To solve this problem, we need to find the common difference of the arithmetic progression (AP) and then use it to find the common ratio of the geometric progression (GP).

Let's start by defining the AP. We are given that the 12th term is 7 times the 2nd term, which can be written as:

a + 11d = 7(a + d)

Simplifying this equation, we get:

a + 11d = 7a + 7d
4a = 4d
a = d

So, the common difference of the AP is equal to the first term, a.

Next, we are given that the 8th term is 3 more than 10 times the first term, which can be written as:

a + 7d = 10a + 3

Simplifying this equation, we get:

7d = 9a + 3
7d - 3 = 9a
7(a) - 3 = 9a
3 = 2a
a = 3/2

So, the first term of the AP is 3/2 and the common difference is also 3/2.

Now, let's move on to finding the common ratio of the GP. The common ratio of a GP can be found by dividing any term by its preceding term. In this case, we will divide the 5th term by the 4th term.

The 4th term of the AP can be found by substituting n = 4 into the AP formula:

a + (4-1)d = a + 3d
3/2 + 3/2 = 3

The 5th term of the AP can be found by substituting n = 5 into the AP formula:

a + (5-1)d = a + 4d
3/2 + 4(3/2) = 9

Therefore, the common ratio of the GP is:

9/3 = 3

So, the first term of the GP is 3/2 and the common ratio is 3. To find the 5th term of the GP, we can use the formula for the nth term of a GP:

Tn = ar^(n-1)

Substituting the values, we get:

T5 = (3/2)(3)^(5-1)
T5 = (3/2)(3)^4
T5 = (3/2)(81)
T5 = 243/2

Therefore, the 5th term of the GP is 243/2.

Since none of the given options match with 243/2, the correct answer is option 'D', None of these.
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In an A.P, the 12th term is 7 times the 2nd term and the 8th term is 3 more than 10 times the first term. What is the 5th term of the G.P whose first term is the first term of A.P and whose common ratio is equal to the common difference of the A.P.a)152b)144c)156d)None of theseCorrect answer is option 'D'. Can you explain this answer?
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