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The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer?.

Solutions for The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The formation of the oxide i on O2-(g) requires first an exothermic and then an endothermic step as shown belowO(g) + e- = O-(g) ΔHº =-142 kJmol-1 [2004]O-(g) + e- = O2-(g) ΔHº= 844 kJmol-1This is becausea)O– ion will ten d to r esist th e addition of another electronb)Oxygen has high electron affinityc)Oxygen is more elecronegatived)O– ion has comparatively larger size than oxygen atomCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.