Class 7 Exam  >  Class 7 Questions  >  One gram of ice is mixed with one gram of ste... Start Learning for Free
One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture is
  • a)
    0°C
  • b)
    50°C
  • c)
    80°C
  • d)
    100°C
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
One gram of ice is mixed with one gram of steam. At thermal equilibriu...
Heat required melting 1g of ice at 0 degree to water at 0 degree = 80 cal
Heat required to raise the temperature of 1 g of water from 0 degree to 100 degree = 1 x 1 x 100 =100cal
Total heat required for maximum temperature of 100 = 180 cal
1 g of steam gives 540 cal so the temperature of mixture will be 100 degrees.
View all questions of this test
Most Upvoted Answer
One gram of ice is mixed with one gram of steam. At thermal equilibriu...
Free Test
Community Answer
One gram of ice is mixed with one gram of steam. At thermal equilibriu...
Explore Courses for Class 7 exam

Top Courses for Class 7

One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer?
Question Description
One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer? for Class 7 2025 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 7 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer?.
Solutions for One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 7. Download more important topics, notes, lectures and mock test series for Class 7 Exam by signing up for free.
Here you can find the meaning of One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of mixture isa)0°Cb)50°Cc)80°Cd)100°CCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 7 tests.
Explore Courses for Class 7 exam

Top Courses for Class 7

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev