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In S polarisation, the electric field lies in the plane perpendicular to that of the interface. State True/False
  • a)
    True
  • b)
    False
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In S polarisation, the electric field lies in the plane perpendicular ...
Answer: a
Explanation: In the EM wave propagation, the electric and magnetic fields are perpendicular to each other. The S polarised wave is similar to the transverse magnetic (TM) wave, the electric field lies in the plane perpendicular to that of the interface.
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Most Upvoted Answer
In S polarisation, the electric field lies in the plane perpendicular ...
Explanation:
In S polarisation, the electric field lies in the plane perpendicular to that of the interface. Let's break down this statement to understand it better.

Definition of S Polarisation:
- S polarisation refers to a type of polarisation where the electric field of an electromagnetic wave is perpendicular to the plane of incidence.

Electric Field Orientation:
- For S polarisation, the electric field vector is parallel to the plane of polarisation and perpendicular to the direction of propagation.
- This means that the electric field lies in the plane perpendicular to the interface between two media.

Relationship with Interface:
- When an electromagnetic wave encounters an interface between two media, the orientation of the electric field determines the type of polarisation.
- In the case of S polarisation, the electric field is oriented such that it is perpendicular to the interface.

Conclusion:
- Therefore, it is true that in S polarisation, the electric field lies in the plane perpendicular to that of the interface. This characteristic distinguishes S polarisation from other types of polarisation such as P polarisation.
By understanding the orientation of the electric field in S polarisation, we can better grasp how electromagnetic waves behave at interfaces and how different types of polarisation impact wave propagation.
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In S polarisation, the electric field lies in the plane perpendicular to that of the interface. State True/Falsea)Trueb)FalseCorrect answer is option 'A'. Can you explain this answer?
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