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Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = sin wt. The phase difference is -900.
- a)Left hand circularly polarised
- b)Right hand circularly polarised
- c)Left hand elliptically polarised
- d)Right hand elliptically polarised
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = si...
Answer: d
Explanation: The magnitude of the Ex and Ey components are not same. Thus it is elliptical polarisation. For -90 phase difference, the polarisation is right handed. In other words, the rotation is in anti-clockwise direction. Thus the polarisation is right hand elliptical.
Explanation: The magnitude of the Ex and Ey components are not same. Thus it is elliptical polarisation. For -90 phase difference, the polarisation is right handed. In other words, the rotation is in anti-clockwise direction. Thus the polarisation is right hand elliptical.
Most Upvoted Answer
Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = si...
Polarisation of the wave:
The given wave has two components: Ex = 2 cos wt and Ey = sin wt. To determine the polarisation of the wave, we need to analyze the relationship between the electric field components Ex and Ey.
Step 1: Analyzing the phase difference:
The given wave has a phase difference of -900. This means that the Ey component lags behind the Ex component by 900 in phase.
Step 2: Identifying the type of polarisation:
To determine the type of polarisation, we need to consider the relationship between the amplitudes and phase difference of the electric field components.
- If the amplitudes of Ex and Ey are equal and the phase difference is ±900, the wave is circularly polarised.
- If the amplitudes of Ex and Ey are unequal and the phase difference is ±900, the wave is elliptically polarised.
Step 3: Comparing the amplitudes:
The given wave has Ex = 2 cos wt and Ey = sin wt. Since the amplitudes of Ex and Ey are not equal, we can conclude that the wave is elliptically polarised.
Step 4: Determining the handedness of elliptical polarisation:
To determine the handedness of elliptical polarisation (whether it is left-handed or right-handed), we need to examine the phase difference.
Since the phase difference is -900, the wave is right-hand elliptically polarised. This means that the electric field vector traces out an elliptical path in the right-handed direction.
Conclusion:
Based on the analysis, we can conclude that the given wave is right-hand elliptically polarised.
The given wave has two components: Ex = 2 cos wt and Ey = sin wt. To determine the polarisation of the wave, we need to analyze the relationship between the electric field components Ex and Ey.
Step 1: Analyzing the phase difference:
The given wave has a phase difference of -900. This means that the Ey component lags behind the Ex component by 900 in phase.
Step 2: Identifying the type of polarisation:
To determine the type of polarisation, we need to consider the relationship between the amplitudes and phase difference of the electric field components.
- If the amplitudes of Ex and Ey are equal and the phase difference is ±900, the wave is circularly polarised.
- If the amplitudes of Ex and Ey are unequal and the phase difference is ±900, the wave is elliptically polarised.
Step 3: Comparing the amplitudes:
The given wave has Ex = 2 cos wt and Ey = sin wt. Since the amplitudes of Ex and Ey are not equal, we can conclude that the wave is elliptically polarised.
Step 4: Determining the handedness of elliptical polarisation:
To determine the handedness of elliptical polarisation (whether it is left-handed or right-handed), we need to examine the phase difference.
Since the phase difference is -900, the wave is right-hand elliptically polarised. This means that the electric field vector traces out an elliptical path in the right-handed direction.
Conclusion:
Based on the analysis, we can conclude that the given wave is right-hand elliptically polarised.
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Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = sin wt. The phase difference is -900.a)Left hand circularly polarisedb)Right hand circularly polarisedc)Left hand elliptically polarisedd)Right hand elliptically polarisedCorrect answer is option 'D'. Can you explain this answer?
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Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = sin wt. The phase difference is -900.a)Left hand circularly polarisedb)Right hand circularly polarisedc)Left hand elliptically polarisedd)Right hand elliptically polarisedCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = sin wt. The phase difference is -900.a)Left hand circularly polarisedb)Right hand circularly polarisedc)Left hand elliptically polarisedd)Right hand elliptically polarisedCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = sin wt. The phase difference is -900.a)Left hand circularly polarisedb)Right hand circularly polarisedc)Left hand elliptically polarisedd)Right hand elliptically polarisedCorrect answer is option 'D'. Can you explain this answer?.
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