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Identify the polarisation of the wave given that, Ex = 2 cos wt and Ey = cos wt.
- a)Elliptical
- b)Circular
- c)Parallel
- d)Linear
Correct answer is option 'D'. Can you explain this answer?
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Identify the polarisation of the wave given that, Ex = 2 cos wt and Ey...
Answer: d
Explanation: The magnitude of the Ex and Ey components are not the same. Thus it cannot be circular polarisation. For a phase difference of 0, the polarisation is linear. In other words, the waves are in phase. Thus the polarisation is linear.
Explanation: The magnitude of the Ex and Ey components are not the same. Thus it cannot be circular polarisation. For a phase difference of 0, the polarisation is linear. In other words, the waves are in phase. Thus the polarisation is linear.
Most Upvoted Answer
Identify the polarisation of the wave given that, Ex = 2 cos wt and Ey...
Polarisation of the wave:
Polarisation refers to the orientation of the electric field vector of a wave. It describes the spatial orientation of the wave as it propagates through space. There are four types of polarisation: linear, circular, elliptical, and unpolarised.
Given wave components:
Ex = 2 cos wt
Ey = cos wt
Analysis:
To determine the polarisation of the wave, we need to examine the components of the electric field in the x and y directions.
Electric field in the x direction (Ex):
Ex = 2 cos wt
Electric field in the y direction (Ey):
Ey = cos wt
We can see that the magnitudes of Ex and Ey are different. This indicates that the wave is not circular or elliptical polarised as they require the same magnitude for both components.
Linear polarisation:
Linear polarisation occurs when the electric field vector oscillates in a single plane. In this case, the electric field components Ex and Ey can be added together to form the resultant electric field vector.
Resultant electric field vector:
E = Ex + Ey
Substituting the given values:
E = 2 cos wt + cos wt
E = 3 cos wt
Conclusion:
Since the resultant electric field vector E is proportional to cos wt, which represents a simple harmonic motion in a single plane, the polarisation of the wave is linear. Therefore, the correct answer is option D) Linear.
Polarisation refers to the orientation of the electric field vector of a wave. It describes the spatial orientation of the wave as it propagates through space. There are four types of polarisation: linear, circular, elliptical, and unpolarised.
Given wave components:
Ex = 2 cos wt
Ey = cos wt
Analysis:
To determine the polarisation of the wave, we need to examine the components of the electric field in the x and y directions.
Electric field in the x direction (Ex):
Ex = 2 cos wt
Electric field in the y direction (Ey):
Ey = cos wt
We can see that the magnitudes of Ex and Ey are different. This indicates that the wave is not circular or elliptical polarised as they require the same magnitude for both components.
Linear polarisation:
Linear polarisation occurs when the electric field vector oscillates in a single plane. In this case, the electric field components Ex and Ey can be added together to form the resultant electric field vector.
Resultant electric field vector:
E = Ex + Ey
Substituting the given values:
E = 2 cos wt + cos wt
E = 3 cos wt
Conclusion:
Since the resultant electric field vector E is proportional to cos wt, which represents a simple harmonic motion in a single plane, the polarisation of the wave is linear. Therefore, the correct answer is option D) Linear.
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