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Identify the polarisation of the wave given that, Ex = 2 sin wt and Ey = 3 sin wt.
  • a)
    Linear
  • b)
    Elliptical
  • c)
    Circular
  • d)
    Parallel
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Identify the polarisation of the wave given that, Ex = 2 sin wt and Ey...
Answer: a
Explanation: The magnitude of the Ex and Ey components are not the same. Thus it cannot be circular polarisation. For a phase difference of 0, the polarisation is linear. In other words, the waves are in phase. Thus the polarisation is linear.
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Identify the polarisation of the wave given that, Ex = 2 sin wt and Ey...
Polarisation of the Wave:

The polarisation of a wave refers to the orientation of the electric field vector as the wave propagates through space. It describes how the electric field oscillates in relation to the direction of wave propagation. There are three main types of polarisation: linear, elliptical, and circular.

Given Electric Field Components:

In this question, we are given the electric field components Ex and Ey as follows:

Ex = 2 sin wt
Ey = 3 sin wt

Here, w represents the angular frequency and t represents time.

Determining the Polarisation:

To determine the polarisation of the wave, we can analyze the given electric field components.

If the wave is linearly polarised, the electric field vector oscillates in a single plane as the wave propagates. This means that the electric field vector can be represented as a linear combination of two mutually perpendicular components.

If the wave is elliptically polarised, the electric field vector traces out an ellipse as the wave propagates. This means that the electric field vector cannot be represented as a linear combination of two mutually perpendicular components.

If the wave is circularly polarised, the electric field vector traces out a circle as the wave propagates. This means that the electric field vector cannot be represented as a linear combination of two mutually perpendicular components.

If the wave is unpolarised or randomly polarised, the electric field vector does not have a specific orientation and changes randomly over time.

Analysis of Given Electric Field Components:

In this case, the given electric field components Ex and Ey are both sinusoidal functions of time (t). However, they are not orthogonal to each other. The presence of both Ex and Ey with different magnitudes and same phase (wt) indicates that the electric field vector is oriented at an angle between the x and y axes.

Since the electric field vector cannot be represented as a linear combination of two mutually perpendicular components (Ex and Ey), the wave is not linearly polarised. Thus, the correct answer is option 'A' - Linear.
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Identify the polarisation of the wave given that, Ex = 2 sin wt and Ey = 3 sin wt.a)Linearb)Ellipticalc)Circulard)ParallelCorrect answer is option 'A'. Can you explain this answer?
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