Two places A and B are at a distance of 480Km. Sita started from A tow...
t*40+ (t-2)*60 = 480
t=6
From Place C to A = C to B = 240
Then time taken by Sita = 6hours and GIta = 4 hours
Difference = 6-4 = 2 hours
View all questions of this test
Two places A and B are at a distance of 480Km. Sita started from A tow...
t*40+ (t-2)*60 = 480
t=6
From Place C to A = C to B = 240
Then time taken by Sita = 6hours and GIta = 4 hours
Difference = 6-4 = 2 hours
Two places A and B are at a distance of 480Km. Sita started from A tow...
Problem Statement:
Two places A and B are at a distance of 480Km. Sita started from A towards B at the speed of 40Kmph. After 2 hours Gita started from B towards A at a speed of 60 Kmph. They meet at a Place C then what is the difference between the time taken by them to reach their destinations from Place C?
Solution:
Let the distance travelled by Sita from A to C be 'x' km. Then the distance travelled by Gita from B to C will be (480 - x) km.
Time taken by Sita to reach C = x/40 hours
Time taken by Gita to reach C = (480 - x)/60 hours
They meet at Place C. So, the time taken by Sita and Gita to reach Place C will be the same.
x/40 = (480 - x)/60
6x = 24000 - 4x
10x = 24000
x = 2400
Therefore, Sita travels 240 km and Gita travels (480 - 240) = 240 km to reach Place C.
Now, the time taken by Sita to reach her destination from Place C will be:
Time taken by Sita = distance/speed = (480 - 240)/40 = 6 hours
The time taken by Gita to reach her destination from Place C will be:
Time taken by Gita = distance/speed = 240/60 = 4 hours
Therefore, the difference between the time taken by them to reach their destinations from Place C is:
Time taken by Sita - Time taken by Gita = 6 - 4 = 2 hours
Hence, the correct answer is option B) 2 hours.