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Find the ratio of the refractive index of medium 1 to that of medium 2, when the incident and reflected angles are given by 300 and 450 respectively.
  • a)
    0.5
  • b)
    1
  • c)
    2
  • d)
    4
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Find the ratio of the refractive index of medium 1 to that of medium 2...
Answer: c
Explanation: The Snell law is given by N1 sin θi = N2 sin θt. For getting N1/N2, the ratio is sin θt/sin θi. On substituting for θi = 30 and θt = 45, we get sin 45/sin 30 = 2.
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Most Upvoted Answer
Find the ratio of the refractive index of medium 1 to that of medium 2...
Given: Incident angle (i) = 30°, Reflected angle (r) = 45°

We know that the ratio of sine of the incident angle to sine of the refracted angle is equal to the ratio of refractive indices of the two media.

Mathematically, n1/n2 = sin r/sin i

Substituting the given values, we get:

n1/n2 = sin 45°/sin 30°

n1/n2 = (1/√2)/(1/2)

n1/n2 = 2/√2

Multiplying numerator and denominator by √2, we get:

n1/n2 = 2√2/2

n1/n2 = √2

Therefore, the ratio of the refractive index of medium 1 to that of medium 2 is √2 or approximately 1.4.

Hence, the correct option is (c) 2.
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Find the ratio of the refractive index of medium 1 to that of medium 2, when the incident and reflected angles are given by 300 and 450 respectively.a)0.5b)1c)2d)4Correct answer is option 'C'. Can you explain this answer?
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