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A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb is
- a)80 W
- b)1800 W
- c)112.5 W
- d)228 W
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A battery has a short-circuit current of 30 A and an open circuit volt...
Ohms, what will be the current flowing through the bulb when it is connected to the battery?
To find the current flowing through the bulb, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) across the circuit divided by the resistance (R) of the circuit.
Using this formula, we can calculate the current flowing through the bulb as:
I = V / R
Where:
I = current flowing through the bulb
V = voltage across the circuit (open circuit voltage of the battery)
R = resistance of the circuit (resistance of the bulb)
Given:
Open circuit voltage of the battery (V) = 24 V
Resistance of the bulb (R) = 2 Ohms
Plugging in these values into the formula, we get:
I = 24 V / 2 Ohms = 12 A
Therefore, the current flowing through the bulb when connected to the battery will be 12 Amperes.
To find the current flowing through the bulb, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) across the circuit divided by the resistance (R) of the circuit.
Using this formula, we can calculate the current flowing through the bulb as:
I = V / R
Where:
I = current flowing through the bulb
V = voltage across the circuit (open circuit voltage of the battery)
R = resistance of the circuit (resistance of the bulb)
Given:
Open circuit voltage of the battery (V) = 24 V
Resistance of the bulb (R) = 2 Ohms
Plugging in these values into the formula, we get:
I = 24 V / 2 Ohms = 12 A
Therefore, the current flowing through the bulb when connected to the battery will be 12 Amperes.
Community Answer
A battery has a short-circuit current of 30 A and an open circuit volt...
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A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)112.5 Wd)228 WCorrect answer is option 'C'. Can you explain this answer?
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A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)112.5 Wd)228 WCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)112.5 Wd)228 WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)112.5 Wd)228 WCorrect answer is option 'C'. Can you explain this answer?.
A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)112.5 Wd)228 WCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)112.5 Wd)228 WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)112.5 Wd)228 WCorrect answer is option 'C'. Can you explain this answer?.
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