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A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb is
  • a)
    80 W
  • b)
    1800 W
  • c)
    146.93 W
  • d)
    228 W
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A battery has a short-circuit current of 30 A and an open circuit volt...
 0.8
146.93
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Most Upvoted Answer
A battery has a short-circuit current of 30 A and an open circuit volt...
R of battery=(24/30)=0.8
now battery voltage 24v battery resistance 0.8 ohms and bulb resistance 2ohms form a ckt 
on solving we get i=(v/(R+r))=(24/(0.8+2))=8.5714
we have power= i^2*r = square of (8.5714) *2 =146.93w
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Community Answer
A battery has a short-circuit current of 30 A and an open circuit volt...
The formula we can use to calculate the current flowing through the bulb is Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R):

I = V / R

Given that the open circuit voltage of the battery is 24 V and the resistance of the bulb is 2 Ω, we can substitute these values into the equation:

I = 24 V / 2 Ω = 12 A

Therefore, the current flowing through the bulb is 12 A.
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A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)146.93 Wd)228 WCorrect answer is option 'C'. Can you explain this answer?
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A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)146.93 Wd)228 WCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)146.93 Wd)228 WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 Ω, the power dissipated by the bulb isa)80 Wb)1800 Wc)146.93 Wd)228 WCorrect answer is option 'C'. Can you explain this answer?.
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