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The equivalent inductances of two coils 2H and 5H in series aiding flux with mutual inductance of 3H is
- a)10
- b)30
- c)1
- d)13
Correct answer is option 'D'. Can you explain this answer?
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The equivalent inductances of two coils 2H and 5H in series aiding flu...
Answer: d
Explanation: The equivalent inductance of two coils in series is given by L = L1 + L2 + 2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L = 2 + 5 + 2(3) = 13H.
Explanation: The equivalent inductance of two coils in series is given by L = L1 + L2 + 2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L = 2 + 5 + 2(3) = 13H.
Most Upvoted Answer
The equivalent inductances of two coils 2H and 5H in series aiding flu...
The equivalent inductance of two coils in series aiding flux can be determined using the concept of mutual inductance. Here, we have two coils with inductances of 2H and 5H, respectively, and a mutual inductance of 3H.
To find the equivalent inductance of the coils in series aiding flux, we can use the formula:
L_eq = L1 + L2 + 2M
where L_eq is the equivalent inductance, L1 and L2 are the individual inductances of the coils, and M is the mutual inductance between the coils.
Now, let's plug in the given values:
L_eq = 2H + 5H + 2(3H)
= 2H + 5H + 6H
= 13H
Therefore, the equivalent inductance of the two coils in series aiding flux is 13H.
Let's summarize the steps:
1. Given inductances: L1 = 2H, L2 = 5H
2. Given mutual inductance: M = 3H
3. Use the formula: L_eq = L1 + L2 + 2M
4. Substitute the given values: L_eq = 2H + 5H + 2(3H)
5. Simplify the expression: L_eq = 2H + 5H + 6H
6. Calculate the equivalent inductance: L_eq = 13H
Therefore, the correct answer is option D) 13.
To find the equivalent inductance of the coils in series aiding flux, we can use the formula:
L_eq = L1 + L2 + 2M
where L_eq is the equivalent inductance, L1 and L2 are the individual inductances of the coils, and M is the mutual inductance between the coils.
Now, let's plug in the given values:
L_eq = 2H + 5H + 2(3H)
= 2H + 5H + 6H
= 13H
Therefore, the equivalent inductance of the two coils in series aiding flux is 13H.
Let's summarize the steps:
1. Given inductances: L1 = 2H, L2 = 5H
2. Given mutual inductance: M = 3H
3. Use the formula: L_eq = L1 + L2 + 2M
4. Substitute the given values: L_eq = 2H + 5H + 2(3H)
5. Simplify the expression: L_eq = 2H + 5H + 6H
6. Calculate the equivalent inductance: L_eq = 13H
Therefore, the correct answer is option D) 13.
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