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Find the torque in a conductor having current 2A, flux density 50 units, length 15cm and distance of 8m.
- a)120
- b)240
- c)800
- d)350
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Find the torque in a conductor having current 2A, flux density 50 unit...
Answer: a
Explanation: The torque on a conductor is given by T = BILd, where L x d is the area of the conductor. Thus the torque will be, T = 50 x 2 x 0.15 x 8 = 120 units.
Explanation: The torque on a conductor is given by T = BILd, where L x d is the area of the conductor. Thus the torque will be, T = 50 x 2 x 0.15 x 8 = 120 units.
Most Upvoted Answer
Find the torque in a conductor having current 2A, flux density 50 unit...
Calculation of Torque in a Conductor
Torque in a conductor can be calculated using the formula:
\[ Torque = I \cdot B \cdot l \cdot d \cdot \sin(\theta) \]
Given Data:
- Current (I) = 2A
- Flux density (B) = 50 units
- Length of the conductor (l) = 15 cm = 0.15 m
- Distance (d) = 8 m
Calculations:
- Convert length to meters: \( l = 0.15 \, m \)
- Determine the angle between the current and the magnetic field (θ) which is usually 90 degrees in such cases: \( \theta = 90^\circ = \frac{\pi}{2} \, rad \)
Substitute Values:
\[ Torque = 2 \cdot 50 \cdot 0.15 \cdot 8 \cdot \sin(\frac{\pi}{2}) \]
\[ Torque = 2 \cdot 50 \cdot 0.15 \cdot 8 \cdot 1 \]
\[ Torque = 120 \, Nm \]
Therefore, the torque in the conductor is 120 Nm, which corresponds to option 'A'.
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Find the torque in a conductor having current 2A, flux density 50 units, length 15cm and distance of 8m.a)120b)240c)800d)350Correct answer is option 'A'. Can you explain this answer?
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