Find the electric field when the velocity of the field is 12m/s and th...
Answer: b
Explanation: The electric field intensity is the product of the velocity and the magnetic flux density ie, E = v x B = 12 x 8.75 = 105 units.
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Find the electric field when the velocity of the field is 12m/s and th...
To find the electric field, we can use the equation:
E = v * B
where E is the electric field, v is the velocity of the field, and B is the flux density.
Given:
v = 12 m/s
B = 8.75 units
Substituting these values into the equation, we have:
E = 12 * 8.75
Calculating this, we get:
E = 105 units
Therefore, the electric field is 105 units.
Explanation:
The electric field is a vector quantity that describes the force experienced by a charged particle in an electric field. It is defined as the force per unit charge.
The equation E = v * B relates the electric field to the velocity of the field and the flux density. The flux density, also known as the magnetic field intensity, represents the strength and direction of the magnetic field.
In this case, the velocity of the field is given as 12 m/s and the flux density is given as 8.75 units. By substituting these values into the equation, we can calculate the electric field.
Multiplying the velocity (12 m/s) by the flux density (8.75 units), we get 105 units. Therefore, the electric field is 105 units.
Conclusion:
The correct answer is option 'B', which states that the electric field is 105 units. This is obtained by multiplying the velocity of the field (12 m/s) by the flux density (8.75 units) using the equation E = v * B.
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