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The electric field intensity of a field with velocity 10m/s and flux density of 2.8 units is
- a)0.28
- b)28
- c)280
- d)10/2.8
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The electric field intensity of a field with velocity 10m/s and flux d...
Answer: b
Explanation: The electric field is the product of the velocity and the magnetic flux density given by E = v x B. On substituting v = 10 and B = 2.8, we get E = 10 x 2.8 = 28 units.
Explanation: The electric field is the product of the velocity and the magnetic flux density given by E = v x B. On substituting v = 10 and B = 2.8, we get E = 10 x 2.8 = 28 units.
Most Upvoted Answer
The electric field intensity of a field with velocity 10m/s and flux d...
Given data:
- Velocity of the field = 10m/s
- Flux density = 2.8 units
Calculation:
Electric field intensity (E) is given by the formula:
E = flux density (B) * velocity (V)
Substitute the given values into the formula:
E = 2.8 * 10
E = 28 units
Therefore, the electric field intensity of the field with a velocity of 10m/s and flux density of 2.8 units is 28 units.
Correct Answer:
Option B) 28
Therefore, the correct answer is option B) 28.
- Velocity of the field = 10m/s
- Flux density = 2.8 units
Calculation:
Electric field intensity (E) is given by the formula:
E = flux density (B) * velocity (V)
Substitute the given values into the formula:
E = 2.8 * 10
E = 28 units
Therefore, the electric field intensity of the field with a velocity of 10m/s and flux density of 2.8 units is 28 units.
Correct Answer:
Option B) 28
Therefore, the correct answer is option B) 28.
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