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The magnetic vector potential for a line current will be inversely proportional to
  • a)
    dL
  • b)
    I
  • c)
    J
  • d)
    R
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The magnetic vector potential for a line current will be inversely pro...
Answer: d
Explanation: The magnetic vector potential for the line integral will be A = ∫ μIdL/4πR. It is clear that the potential is inversely proportional to the distance or radius R.
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Most Upvoted Answer
The magnetic vector potential for a line current will be inversely pro...
Explanation:
The magnetic vector potential (A) is a vector field that describes the magnetic field generated by a current-carrying wire or conductor. It is defined as the line integral of the magnetic field (B) around a closed loop divided by the permeability of free space (μ₀).

Magnetic Vector Potential (A) = (μ₀/4π) ∮ B · dl

Where:
- A is the magnetic vector potential
- μ₀ is the permeability of free space (4π × 10^-7 H/m)
- B is the magnetic field
- ∮ represents a closed line integral
- dl is an infinitesimal vector element along the path of integration

The current flowing through a wire or conductor produces a magnetic field around it. The magnetic vector potential describes this field and its relationship with the current.

Inversely Proportional Relationship:
The magnetic vector potential for a line current is inversely proportional to the resistance (R) of the wire or conductor. This can be explained using the following points:

1. Ampere's Law:
Ampere's law relates the magnetic field around a closed loop to the current passing through the loop. It states that the line integral of the magnetic field (B) around a closed loop is equal to the permeability of free space (μ₀) times the total current enclosed by the loop.

∮ B · dl = μ₀I_enclosed

2. Magnetic Vector Potential:
The magnetic vector potential (A) is related to the magnetic field (B) through the equation:

B = ∇ × A

Where ∇ is the del operator.

3. Relationship between A and I:
Substituting the expression for B from Ampere's law into the equation for A, we get:

∇ × A = μ₀I_enclosed

Taking the curl of both sides, we have:

∇ × (∇ × A) = μ₀∇ × I_enclosed

Simplifying this equation using vector calculus identities, we obtain:

∇(∇ · A) - ∇²A = μ₀∇ × I_enclosed

4. Scalar Magnetic Potential:
If we assume that the current distribution is such that ∇ × I_enclosed = 0 (which holds for a line current), then the equation simplifies to:

∇²A = -μ₀∇ · I_enclosed = -μ₀J

Where J is the current density.

5. Poisson's Equation:
The equation obtained in the previous step is known as Poisson's equation. It relates the Laplacian of the magnetic vector potential (A) to the current density (J).

∇²A = -μ₀J

6. Inverse Proportional Relationship:
From Poisson's equation, we can observe that the Laplacian of the magnetic vector potential is proportional to the current density. Since the current density is inversely proportional to the resistance (J = I/R), we can conclude that the magnetic vector potential (A) is inversely proportional to the resistance (R).
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The magnetic vector potential for a line current will be inversely proportional toa)dLb)Ic)Jd)RCorrect answer is option 'D'. Can you explain this answer?
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