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Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A.
  • a)
    250
  • b)
    325
  • c)
    175
  • d)
    375
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Find the magnetic field intensity due to a solenoid of length 12cm hav...
Answer: d
Explanation: The magnetic field intensity of a solenoid is given by H = NI/L = 30 X 1.5/0.12 = 375 units.
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Find the magnetic field intensity due to a solenoid of length 12cm hav...
Magnetic Field Intensity due to a Solenoid:

The magnetic field intensity (B) inside a solenoid can be calculated using the formula:

B = μ₀ * n * I

Where:
B is the magnetic field intensity,
μ₀ is the permeability of free space (4π * 10^-7 T.m/A),
n is the number of turns per unit length,
I is the current flowing through the solenoid.

Given data:
Length of the solenoid, L = 12 cm = 0.12 m
Number of turns, n = 30
Current, I = 1.5 A

Calculating the Magnetic Field Intensity:

1. First, we need to calculate the number of turns per unit length (n).
n = Number of turns / Length
= 30 / 0.12
= 250 turns/m

2. Now, we can calculate the magnetic field intensity (B).
B = μ₀ * n * I
= (4π * 10^-7) * 250 * 1.5
≈ 375 T (Tesla)

Therefore, the magnetic field intensity due to the solenoid is approximately 375 T.
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Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A.a)250b)325c)175d)375Correct answer is option 'D'. Can you explain this answer?
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