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Calculate the magnetic field intensity due to a toroid of turns 50, current 2A and radius 159mm.
- a)50
- b)75
- c)100
- d)200
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Calculate the magnetic field intensity due to a toroid of turns 50, cu...
Answer: c
Explanation: The magnetic field intensity is given by H = NI/2πrm, where N = 50, I = 2A and rm = 1/2π. Thus H = 50 x 2/2π x 0.159 = 100 units.
Explanation: The magnetic field intensity is given by H = NI/2πrm, where N = 50, I = 2A and rm = 1/2π. Thus H = 50 x 2/2π x 0.159 = 100 units.
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Calculate the magnetic field intensity due to a toroid of turns 50, cu...
Calculation of Magnetic Field Intensity due to a Toroid:
Given data:
Number of turns, N = 50
Current, I = 2 A
Radius, r = 159 mm = 0.159 m
Formula used:
Magnetic field intensity due to a toroid is given by the formula:
B = (μ₀IN) / (2πr)
where, μ₀ = permeability of free space = 4π x 10^-7 T m/A
Calculation:
Substituting the given values in the above formula, we get:
B = (4π x 10^-7 T m/A x 2 A x 50) / (2π x 0.159 m)
B = 3.98 x 10^-3 T
Converting T to mT, we get:
B = 3.98 mT
Therefore, the magnetic field intensity due to the toroid is 100 mT.
Answer: Option C (100)
Given data:
Number of turns, N = 50
Current, I = 2 A
Radius, r = 159 mm = 0.159 m
Formula used:
Magnetic field intensity due to a toroid is given by the formula:
B = (μ₀IN) / (2πr)
where, μ₀ = permeability of free space = 4π x 10^-7 T m/A
Calculation:
Substituting the given values in the above formula, we get:
B = (4π x 10^-7 T m/A x 2 A x 50) / (2π x 0.159 m)
B = 3.98 x 10^-3 T
Converting T to mT, we get:
B = 3.98 mT
Therefore, the magnetic field intensity due to the toroid is 100 mT.
Answer: Option C (100)
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