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Without feedback, the voltage gain is 40 and distortion is 10%, if feedback factor of -0.01 (negative feedback) is given to the amplifier, the distortion will be
- a)5%
- b)7.14%
- c)9%
- d)1%
Correct answer is option 'B'. Can you explain this answer?
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Without feedback, the voltage gain is 40 and distortion is 10%, if fee...
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Without feedback, the voltage gain is 40 and distortion is 10%, if fee...
Given information:
- Voltage gain without feedback (A): 40
- Distortion without feedback (D1): 10%
- Feedback factor (β): -0.01
To find: Distortion with feedback (D2)
Formula:
Distortion with feedback (D2) = Distortion without feedback (D1) / (1 + Aβ)
Calculation:
Using the formula, we can calculate the distortion with feedback (D2):
D2 = D1 / (1 + Aβ)
D2 = 10% / (1 + 40 * -0.01)
D2 = 10% / (1 - 0.4)
D2 = 10% / 0.6
D2 = 16.67%
Therefore, the distortion with feedback is approximately 16.67%.
But none of the given options matches this result.
Explanation:
The given answer options are incorrect. The correct answer should be 16.67% or approximately 17%.
The distortion with feedback is always less than the distortion without feedback in a negative feedback configuration. This is because negative feedback reduces the overall gain of the amplifier, which in turn reduces distortion.
In this case, the negative feedback factor (-0.01) is subtracted from 1, which reduces the overall gain of the amplifier. The voltage gain without feedback (40) is large, and when multiplied by the negative feedback factor, it further reduces the gain.
As a result, the distortion with feedback is reduced compared to without feedback. In this case, the distortion is reduced from 10% to approximately 16.67% or 17% with the given negative feedback factor.
So, the correct answer should be approximately 17% (option D), and not any of the given options.
- Voltage gain without feedback (A): 40
- Distortion without feedback (D1): 10%
- Feedback factor (β): -0.01
To find: Distortion with feedback (D2)
Formula:
Distortion with feedback (D2) = Distortion without feedback (D1) / (1 + Aβ)
Calculation:
Using the formula, we can calculate the distortion with feedback (D2):
D2 = D1 / (1 + Aβ)
D2 = 10% / (1 + 40 * -0.01)
D2 = 10% / (1 - 0.4)
D2 = 10% / 0.6
D2 = 16.67%
Therefore, the distortion with feedback is approximately 16.67%.
But none of the given options matches this result.
Explanation:
The given answer options are incorrect. The correct answer should be 16.67% or approximately 17%.
The distortion with feedback is always less than the distortion without feedback in a negative feedback configuration. This is because negative feedback reduces the overall gain of the amplifier, which in turn reduces distortion.
In this case, the negative feedback factor (-0.01) is subtracted from 1, which reduces the overall gain of the amplifier. The voltage gain without feedback (40) is large, and when multiplied by the negative feedback factor, it further reduces the gain.
As a result, the distortion with feedback is reduced compared to without feedback. In this case, the distortion is reduced from 10% to approximately 16.67% or 17% with the given negative feedback factor.
So, the correct answer should be approximately 17% (option D), and not any of the given options.
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Without feedback, the voltage gain is 40 and distortion is 10%, if feedback factor of -0.01 (negative feedback) is given to the amplifier, the distortion will bea)5% b)7.14%c)9% d)1%Correct answer is option 'B'. Can you explain this answer?
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