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An amplifier without feedback has a voltage gain of 50, input resistance of 1 kΩ and output resistance of 2.5 kΩ. The input resistance of the current shunt -ve feedback amplifier using the above amplifier with a feedback factor of 0.2 is
- a)1/11 kΩ
- b)1/5 kΩ
- c)5 kW
- d)11 kW
Correct answer is option 'A'. Can you explain this answer?
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An amplifier without feedback has a voltage gain of 50, input resistan...
Input Resistance with feedback for current shunt, 
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An amplifier without feedback has a voltage gain of 50, input resistan...
Given parameters:
- Voltage gain (Av) = 50
- Input resistance (Rin) = 1 kΩ
- Output resistance (Rout) = 2.5 kΩ
- Feedback factor (β) = 0.2
We need to find the input resistance (Rin') of the current shunt -ve feedback amplifier.
Solution:
The input resistance of the current shunt -ve feedback amplifier is given as:
Rin' = Rin/(1 + β*Av)
Substituting the given values, we get:
Rin' = 1/(1 + 0.2*50) kΩ
Rin' = 1/11 kΩ
Therefore, the input resistance of the current shunt -ve feedback amplifier is 1/11 kΩ.
Explanation:
- Feedback is a technique used to improve the performance of an amplifier.
- In current shunt -ve feedback, a small part of the output voltage is fed back to the input in a way that it opposes the input signal.
- This reduces the input signal seen by the amplifier, which in turn reduces distortion and noise.
- The feedback factor (β) is the fraction of the output voltage that is fed back to the input.
- The voltage gain of an amplifier with feedback (Av') is given as:
Av' = Av/(1 + β*Av)
- The input resistance of an amplifier with feedback (Rin') is given as:
Rin' = Rin/(1 + β*Av)
- In the given problem, we have to find Rin' using the above formula.
- Substituting the given values, we get the answer as 1/11 kΩ.
- Voltage gain (Av) = 50
- Input resistance (Rin) = 1 kΩ
- Output resistance (Rout) = 2.5 kΩ
- Feedback factor (β) = 0.2
We need to find the input resistance (Rin') of the current shunt -ve feedback amplifier.
Solution:
The input resistance of the current shunt -ve feedback amplifier is given as:
Rin' = Rin/(1 + β*Av)
Substituting the given values, we get:
Rin' = 1/(1 + 0.2*50) kΩ
Rin' = 1/11 kΩ
Therefore, the input resistance of the current shunt -ve feedback amplifier is 1/11 kΩ.
Explanation:
- Feedback is a technique used to improve the performance of an amplifier.
- In current shunt -ve feedback, a small part of the output voltage is fed back to the input in a way that it opposes the input signal.
- This reduces the input signal seen by the amplifier, which in turn reduces distortion and noise.
- The feedback factor (β) is the fraction of the output voltage that is fed back to the input.
- The voltage gain of an amplifier with feedback (Av') is given as:
Av' = Av/(1 + β*Av)
- The input resistance of an amplifier with feedback (Rin') is given as:
Rin' = Rin/(1 + β*Av)
- In the given problem, we have to find Rin' using the above formula.
- Substituting the given values, we get the answer as 1/11 kΩ.
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An amplifier without feedback has a voltage gain of 50, input resistance of 1 kΩ and output resistance of 2.5 kΩ. The input resistance of the current shunt -ve feedback amplifier using the above amplifier with a feedback factor of 0.2 isa)1/11 kΩb)1/5 kΩc)5 kWd)11 kWCorrect answer is option 'A'. Can you explain this answer?
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