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The electric flux density of a surface with permittivity of 2 is given by 12 units. What the flux density of the surface in air?
- a)24
- b)6
- c)1/6
- d)0
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The electric flux density of a surface with permittivity of 2 is given...
Answer: b
Explanation: The relation between electric field and permittivity is given by Dt1/Dt2 = ε1/ε2. Put Dt1 = 12, ε1 = 2 and ε2 =1, we get Dt2 = 12 x 1/ 2 = 6 units.
Explanation: The relation between electric field and permittivity is given by Dt1/Dt2 = ε1/ε2. Put Dt1 = 12, ε1 = 2 and ε2 =1, we get Dt2 = 12 x 1/ 2 = 6 units.
Most Upvoted Answer
The electric flux density of a surface with permittivity of 2 is given...
Given data:
- Permittivity of the surface: ε = 2
- Electric flux density: D = 12 units
To find: Electric flux density of the surface in air
Formula:
The electric flux density (D) is given by the equation:
D = εE
where:
- D is the electric flux density
- ε is the permittivity
- E is the electric field intensity
Electric field (E) in air:
Air is considered to be a dielectric material with a permittivity of ε0 = 8.854 x 10^-12 F/m. In air or vacuum, the permittivity is given by ε = ε0.
Therefore, the electric field intensity in air (E) can be calculated as:
E = D / ε0
Calculation:
Given:
D = 12 units
ε = 2
ε0 = 8.854 x 10^-12 F/m
Using the formula for electric field intensity in air:
E = D / ε0
E = 12 / (8.854 x 10^-12)
E ≈ 1.354 x 10^12 V/m
So, the electric field intensity in air is approximately 1.354 x 10^12 V/m.
Flux density in air:
Now, we can calculate the flux density (D) in air using the equation:
D = εE
Using the given permittivity in air (ε0 = 8.854 x 10^-12 F/m) and the calculated electric field intensity in air (E ≈ 1.354 x 10^12 V/m), we can calculate the flux density in air:
D = ε0E
D ≈ (8.854 x 10^-12) x (1.354 x 10^12)
D ≈ 12 units
Therefore, the flux density of the surface in air is approximately 12 units.
Thus, the correct answer is option B) 6.
- Permittivity of the surface: ε = 2
- Electric flux density: D = 12 units
To find: Electric flux density of the surface in air
Formula:
The electric flux density (D) is given by the equation:
D = εE
where:
- D is the electric flux density
- ε is the permittivity
- E is the electric field intensity
Electric field (E) in air:
Air is considered to be a dielectric material with a permittivity of ε0 = 8.854 x 10^-12 F/m. In air or vacuum, the permittivity is given by ε = ε0.
Therefore, the electric field intensity in air (E) can be calculated as:
E = D / ε0
Calculation:
Given:
D = 12 units
ε = 2
ε0 = 8.854 x 10^-12 F/m
Using the formula for electric field intensity in air:
E = D / ε0
E = 12 / (8.854 x 10^-12)
E ≈ 1.354 x 10^12 V/m
So, the electric field intensity in air is approximately 1.354 x 10^12 V/m.
Flux density in air:
Now, we can calculate the flux density (D) in air using the equation:
D = εE
Using the given permittivity in air (ε0 = 8.854 x 10^-12 F/m) and the calculated electric field intensity in air (E ≈ 1.354 x 10^12 V/m), we can calculate the flux density in air:
D = ε0E
D ≈ (8.854 x 10^-12) x (1.354 x 10^12)
D ≈ 12 units
Therefore, the flux density of the surface in air is approximately 12 units.
Thus, the correct answer is option B) 6.
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The electric flux density of a surface with permittivity of 2 is given by 12 units. What the flux density of the surface in air?a)24b)6c)1/6d)0Correct answer is option 'B'. Can you explain this answer?
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