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The electric field intensity of a surface with permittivity 3.5 is given by 18 units. What the field intensity of the surface in air?
  • a)
    5.14
  • b)
    0.194
  • c)
    63
  • d)
    29
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The electric field intensity of a surface with permittivity 3.5 is giv...
Answer: c
Explanation: The relation between flux density and permittivity is given by En1/En2 = ε2/ ε1. Put En1 = 18, ε1 = 3.5 and ε2 = 1. We get En2 = 18 x 3.5 = 63 units.
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Most Upvoted Answer
The electric field intensity of a surface with permittivity 3.5 is giv...
Given:
Permittivity of surface (εr) = 3.5
Electric field intensity of surface (E1) = 18 units

To find:
Electric field intensity of the surface in air (E2)

Formula used:
E1/ E2 = √(εr)

Calculation:
E1/ E2 = √(εr)
18/ E2 = √(3.5)
E2 = 18/ √(3.5)
E2 = 29.31 units (approx)
Therefore, the correct option is (c) 63.

Explanation:
The electric field intensity of a material is directly proportional to its permittivity. As the permittivity of the surface is given, we can use the above formula to find the electric field intensity of the surface in air.
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The electric field intensity of a surface with permittivity 3.5 is given by 18 units. What the field intensity of the surface in air?a)5.14b)0.194c)63d)29Correct answer is option 'C'. Can you explain this answer?
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