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Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ)
- a)3.16
- b)5.16
- c)7.16
- d)9.16
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Calculate the energy in an electric field with permittivity of 56 and ...
Answer: a
Explanation: The energy in an electric field is given by, W = 0.5 x D x E. Since D = εE, we get W = 0.5 x ε x E2. On substituting the data, we get 3.16 microjoule.
Explanation: The energy in an electric field is given by, W = 0.5 x D x E. Since D = εE, we get W = 0.5 x ε x E2. On substituting the data, we get 3.16 microjoule.
Most Upvoted Answer
Calculate the energy in an electric field with permittivity of 56 and ...
The energy (U) in an electric field can be calculated using the formula:
U = (1/2) * ε * E^2
where ε is the permittivity and E is the field intensity.
Given:
ε = 56
E = 36
Plugging in the values into the formula:
U = (1/2) * 56 * 36^2
U = (1/2) * 56 * 1296
U = 28 * 1296
U = 36288
Therefore, the energy in the electric field is 36288.
U = (1/2) * ε * E^2
where ε is the permittivity and E is the field intensity.
Given:
ε = 56
E = 36
Plugging in the values into the formula:
U = (1/2) * 56 * 36^2
U = (1/2) * 56 * 1296
U = 28 * 1296
U = 36288
Therefore, the energy in the electric field is 36288.
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Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ)a)3.16b)5.16c)7.16d)9.16Correct answer is option 'A'. Can you explain this answer?
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