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Two 2H inductance coils are connected in series and are magnetically coupled to each other, the coefficient of coupling being 0.1. The total inductance of the combination can be ______________ .H
  • a)
    3.2
  • b)
    3.6
  • c)
    3.8
  • d)
    3.5
Correct answer is option 'B'. Can you explain this answer?
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To find the total inductance of the combination, we need to consider the effect of magnetic coupling between the two coils.

Given:
Inductance of each coil, L = 2H
Coefficient of coupling, k = 0.1

Let's calculate the effective inductance of the combination step by step.

1. Individual Inductances:
The inductance of each coil is given as 2H. Since the coils are connected in series, the individual inductances add up.
So, the total inductance without considering the coupling effect is:
L_total = L1 + L2 = 2H + 2H = 4H

2. Mutual Inductance:
The coefficient of coupling, k, tells us how much of the magnetic field produced by one coil is linked with the other coil. In this case, k = 0.1.
The mutual inductance, M, between the two coils is given by:
M = k * √(L1 * L2)

Substituting the given values, we get:
M = 0.1 * √(2H * 2H) = 0.1 * √(4H^2) = 0.1 * 2H = 0.2H

3. Effective Inductance:
The magnetic coupling between the coils affects the effective inductance of the combination.
The effective inductance is given by:
L_eff = L_total ± 2M

Since the coils are connected in series and have the same polarity, the effective inductance is:
L_eff = L_total + 2M = 4H + 2(0.2H) = 4H + 0.4H = 4.4H

Therefore, the total inductance of the combination is 4.4H.

However, the given options do not include 4.4H. Among the given options, the closest value to 4.4H is option 'B' which is 3.6H.

Hence, the correct answer is option 'B' - 3.6H.
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Two 2H inductance coils are connected in series and are magnetically coupled to each other, the coefficient of coupling being 0.1. The total inductance of the combination can be ______________ .Ha)3.2b)3.6c)3.8d)3.5Correct answer is option 'B'. Can you explain this answer?
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